Solve Integral with Fourier Transform - Get Help Now!

doublemint
Messages
138
Reaction score
0
Hello!
Can someone help me with this.
Evaluate:
the integral from zero to infinite of ((xcos(x)-sin(x))/x^3)cos(x/2)dx

I think it has to do with Fouriers Transform but I am just stuck.
Any help would be appreciated!
Thank You
 
Physics news on Phys.org
Thanks for the response fzero. There is one problem I have, my class has not covered the Dirichlet Integrals..Is there another method of solving this integral?
 
doublemint said:
Thanks for the response fzero. There is one problem I have, my class has not covered the Dirichlet Integrals..Is there another method of solving this integral?

It doesn't matter whether you covered them or not. I linked you to that page because it shows you how to evaluate them. Adapt the techniques to the integrals you have to do or find another way to do them.
 
doublemint said:
Thanks for the response fzero. There is one problem I have, my class has not covered the Dirichlet Integrals..Is there another method of solving this integral?
You could formally take the Fourier Transform. Let:

\mathcal{F}\left\{f(x)\right\}=\frac{1}{\sqrt{2 \pi }}\int _{-\infty }^{\infty }f(t)e^{i\omega t}dtand suppose that we are given:

<br /> \mathcal{F}\left\{\frac{x\cos(x)-\sin(x)}{x^3}\right\}=\frac{1}{4} \sqrt{\frac{\pi }{2}} \left(-1+w^2\right) (\text{Sign}[1-w]+\text{Sign}[1+w])

Where Sign(x) is either -1,0 or 1 depending on x being negative, zero, or positive. Can you now solve your integral?
 
Last edited:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top