Solve Kinematics: Find Vi of Flea Jumping 0.390m

  • Thread starter Thread starter jnimagine
  • Start date Start date
  • Tags Tags
    Kinematics
AI Thread Summary
To find the initial velocity (Vi) of a flea jumping to a maximum height of 0.390m, the equation vf^2 = vi^2 + 2ad is used, where vf is the final velocity at the peak (0 m/s), a is the acceleration due to gravity (-9.8 m/s²), and d is the height (0.390 m). The negative sign in acceleration indicates that gravity opposes the flea's upward jump. By rearranging the equation, the issue of negative velocity can be resolved by recognizing the directional nature of the vectors involved. Ultimately, the correct application of the kinematic equation allows for the calculation of Vi without confusion over sign conventions.
jnimagine
Messages
176
Reaction score
0
A flea jmps to a maximum height of 0.390m. Find vi as it leaves the ground.

I thought of using the equation vf^2 = vi^2 + 2ad
but in this case, if i want to find out vi, I get
-vi^2 = 2ad.
and because of the negative, it doesn't work...

How do you solve this problem??
 
Physics news on Phys.org
jnimagine said:
A flea jmps to a maximum height of 0.390m. Find vi as it leaves the ground.

I thought of using the equation vf^2 = vi^2 + 2ad
but in this case, if i want to find out vi, I get
-vi^2 = 2ad.
and because of the negative, it doesn't work...

How do you solve this problem??

Acceleration due to gravity: a = -9.8m/s2 note the minus sign!

The reason why this is negative: the flea is jumping up (positive direction), acceleration is acting down (negative direction as it is opposite to the direction of the jump)

This cancels out your problem of negative displacement when you realize you are working with vectors that have different directions.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top