Solve LOG Problem: Evaluate Log 3 (Base 27) Without Calculator

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To evaluate log base 27 of 3 without a calculator, it is essential to understand that log_{27} 3 means finding x such that 27^x = 3. Recognizing that 27 can be expressed as 3^3 simplifies the problem. By rewriting the equation, we find that 3^(3x) = 3, leading to the conclusion that 3x must equal 1. Thus, x equals 1/3, confirming that log_{27} 3 equals 1/3. This method provides a clear step-by-step approach to solving the logarithmic problem.
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1. Evaluate WITHOUT using a calculator.



2. log base 27, 3, that is, log 3 with a base of 27 instead of 10



3. I'm stuck on how you end up with the solution, which is 1/3.

Can someone provide a step by step walk through on how to solve this problem without a calculator?
 
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Well, any number, x, to the power of a fraction is defined such that x^\frac{a}{b} is equal to \sqrt<b>{x^a}</b>. Therefore log_{27} 3 is defined such that 27^x is equal to 3 and the only solution is 27^\frac{1}{3} and this is the same as the \sqrt[3]{27} which is equal to 3.
 
Kevin_Axion said:
Well, any number, x, to the power of a fraction is defined such that x^\frac{a}{b} is equal to \sqrt<b>{x^a}</b>. Therefore log_{27} 3 is defined such that 27^x is equal to 3 and the only solution is 27^\frac{1}{3} and this is the same as the \sqrt[3]{27} which is equal to 3.


Thanks! that helped a lot!:cool:
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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