Solve Mechanics Questions: Velocity, Position & Frictionless Plane

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The discussion revolves around solving mechanics questions related to velocity, position, and motion on a frictionless plane. The first question involves a car with a given acceleration and initial velocity, requiring calculations for velocity and position at time t, as well as distance traveled after a specific time. The second question addresses a box on a vertical incline, asking for the time it takes to fall and the height from which it fell. Participants provide formulas and calculations, but there are discrepancies with the answers, leading to frustration and requests for clarification and graphical representation. Overall, the conversation highlights the challenges of solving physics problems and the importance of verifying calculations.
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Hi, this is my first post. My teacher gave us some very "hard" homework questions:
Alright: The first question concerns a car moving with acceleration 5t^{2} and initial velocity 4 m/s.

a) what is it's velicity at time t?

b) what is it's position at time t?

c) How far has it gone after time t=pi seconds.

2)

a) Assume I have a frictionless plane inclined at pi/2 radians and a box 6 ft up the plane, how long does it take to fall?

b) Assuming the rock took ten seconds to fall, how high did it start up?
 
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Hey!

I remember doing homework with questions like these!

1.
a) Remember, an object's velocity is simply the integral of its accelleration.
So, the integral of 5t^2 is 5/3t^3 + c.
v=5/3t^3 + c.

b) Like the first question, the objects position at time t is the integral of its
velocity, so the position of the object is 5/12t^4 + t + initial position.
d=5/12t^4+t+c.

c) Just use pi in place of t in the position equation.
d=5/12pi^4+pi+c.2.
a) Since a 'ramp' at pi/2 radians is vertical, you can calculate how long the rock
takes to fall using the accelleration of gravity=9.8 m/s^2.
6 = 1/2 * 9.8 * t^2
12 = 9.8 * t^2
12/9.8 = t^2
t = (12/8.8)^1/2 s.

b) height = 1/2 * 9.8 * 10^2
height = 2 * 9.8 * 100
height = 1960 m.

I hope that helps!
 
Your first answer isn't what it says in my teachers manual... But thanks anyways.
 
Oh crap! Your right, I forgot the +c. Editing to fix it...
 
Thanks a lot, I don't trust this manual anyways.
 
Homophome said:
Thanks a lot, I don't trust this manual anyways.

Haha, yeah, you have to think for yourself sometimes!
No problem.
 
Edit: Your asnwers don't work... sorry. : (. Also, webassign requires me to graph position vs. time, could you draw me a graph?
 
Homophome said:
Edit: Your asnwers don't work... sorry. : (. Also, webassign requires me to graph position vs. time, could you draw me a graph?
What? I thought they were right. Maybe double check your variables and that you are typing things in right?
I'm not going to draw a graph, but for the second one with the falling rock, it will look like a decreasing quadratic function. Check my attached graph (not exact... ms paint lol!) for what it may look like if you zoom into the right spot. It will be a decreasing parabala centered on the x=zero.
 

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Where are the units on that graph? It looks like a kid drew that! Not helpful at all. Can someone please help me?!??!
 

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