Solve Motion Position Homework: Answer at 6 sec - 10/46 m

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The homework problem involves calculating the position of an object at 6 seconds, starting from an initial position of 10 m, with a known position of 17 m at 2 seconds. The equation for displacement is provided, but there is uncertainty regarding the final velocity to use in the calculations. The discussion emphasizes that the problem may not involve constant acceleration, suggesting a more complex relationship between velocity and displacement. A hint is given to recall calculus concepts related to motion. The key takeaway is that understanding the relationship between velocity and displacement is crucial for solving the problem accurately.
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Homework Statement



Consider the plot below describing motion along a straight line with an initial position of x = 10 m.

http://img261.imageshack.us/my.php?image=asdfdp5.jpg

What is the position at 6 seconds? Answer in m.

The position at 2 seconds is 17 m.

Homework Equations



delta d = 1/2a delta t^2 + Vi delta t


The Attempt at a Solution



I didn't know whether to use 4 or 0 as the final velocity.

delta d = 10 or 46
 
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The problem is much simpler than it looks. Remember from calculus how velocity and displacement are related.

Hint: Remember that this may not necessarily be a constant acceleration problem.

Bryan
 
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