Solve Simple Motion Prob: Inst. Speed of Bicycle 5m

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SUMMARY

The discussion focuses on calculating the instantaneous speed of a bicycle at the 5m mark during a 1000m sprint, given a constant acceleration and a measured time of 4 seconds to cover the first 10m. The initial attempt incorrectly calculated the instantaneous speed using average velocity, resulting in a value of 3.125 m/s. The correct approach involves using the equation for displacement under constant acceleration, specifically displacement = 1/2 a t^2, to accurately determine the instantaneous speed at the desired distance.

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Homework Statement



Two physics students are trying to determine the instantaneous speed of a bicycle 5m from the start of a 1000m sprint. They use a stopwatch to measure the time taken for the bicyble to cover the first 10m. If the acceleration was constant, and the measured time was 4sec, what was the instantaneous speed of the bicyle at 5m mark?

Homework Equations





The Attempt at a Solution




Method 1:
Find acceleration:
a=change in velocity/change in time
=(displacement/time) /time
= displacement/time^2
= (10-0)/(4-0)^2
=.625m/s^2
Find instantaneous velocity at 5sec:
5 x .625 = 3.125m/s

BUt the answer is wrong. WHy?
 
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Accel = change in velocity / change in time - that's right (equation 1).
Velocity = change in distance / change in time - that's also right.

But when you say "velocty = (10-0)/4" you are finding the AVERAGE velocity over the 4 sec, not the FINAL velocity that you need in equation 1.

The correct equation for constant acceleration is starting from rest is displacement = 1/2 a t^2 Check back to your textbook or notes on motion with constant acceleration.
 

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