Solve the initial value problem explicitly for u

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SUMMARY

The discussion focuses on solving the initial value problem for the differential equation du/dt = (2t + sec^2(t))/2u with the initial condition u(0) = 4. The solution process involves separating variables, leading to the equation 2u*du = (2t + sec^2(t))dt, which is then integrated to yield u^2 = t^2 + tan(t) + C. The constant C is determined by substituting the initial condition, resulting in a complete solution for u.

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  • Understanding of differential equations and initial value problems
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  • Ability to manipulate and solve algebraic equations
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EndOfMemories
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Homework Statement



solve the initial value problem for u

du/dt= (2t + sec^2(t))/2u also, u(0)=4

Homework Equations



antiderivative of sec^2(t) is tan(t) + C

The Attempt at a Solution



So, the first thing i did was move the "u" with the "u" and "t" with the "t". so the equation looks like
2u*du = 2t*dt + sec^2(t)*dt
then anti differentiated and got
u^2 = t^2 + tan(t) + C
then i got stuck
 
Last edited:
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Hi EndOfMemories! :smile:

(try using the X2 icon just above the Reply box :wink:)
EndOfMemories said:
… also, u(0)=4

So, the first thing i did was move the "u" with the "u" and "t" with the "t". so the equation looks like
2u*du = 2t*dt + sec^2(t)*dt
then anti differentiated and got
u^2 = t^2 + tan(t) + C
then i got stuck

that's fine! :smile:

now you need to find C, which you do by putting t = 0 and u = 4 :wink:
 
I see. thanks =)
 

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