Solve Thevenian Theorem: Calculate Voltage Across A and B

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Homework Help Overview

The discussion revolves around applying Thevenin's theorem to calculate the voltage across terminals A and B in a circuit. Participants are exploring the relationships between resistors and voltage sources within the circuit, particularly focusing on the implications of series and parallel configurations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of Thevenin voltage and the relevance of certain resistors in the circuit. There are attempts to clarify the roles of series and parallel components, as well as how to incorporate voltage sources into their calculations.

Discussion Status

The conversation includes various interpretations of how to approach the problem, with some participants offering guidance on using the voltage divider rule and the significance of open circuit conditions. There is a recognition of confusion regarding the treatment of the 12 V battery and its orientation in relation to Thevenin voltage.

Contextual Notes

Participants express uncertainty about identifying series and parallel arrangements in the circuit, which complicates their calculations. The original poster mentions a messy circuit diagram, indicating potential challenges in visualizing the problem accurately.

roshan2004
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This question is based on the thevenian's theorem,but my problem is on the basic rule of circuit.I have come at the stage where I have to calculate the Thevenian's voltage that is "V" across A and B.I know that V=I*6 since V across AB equals to the V across CD as there is no drop of current on the 3 ohms resistor but now I have to calculste I which can be found by V/R(total).V is 36 volt.Now I have to find Total R which is the stage where I am totally confused since I just know how to rearrange the given circuit.I don't know which one is parallel or in series with another.Please have a look on the picture (which is messy).
Your post is valuable or me.
 

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The Thevenin voltage is the open circuit voltage between the terminals A & B. Since you already realize that the 3 Ω resistor is irrelevant, just ignore it. You have a simple series circuit, for which you can find the total resistance and then the current. Use that to find the Thevenin voltage.
 
Thanks,I used the voltage divider rule and got the answer.
 
This is another type of question where I am troubled to calculate the thevenian voltage.The original question is to calculate the current through 10 ohms resistor.
 

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Once again, the Thevenin voltage is the open circuit voltage between A and B. That means there's no current through the 8 Ω resistor (but don't neglect the 12 V battery). Use the voltage divider rule to find the voltage across the 2 Ω resistor.
 
Yeap I really don't know how to treat 12 V battery.
 
roshan2004 said:
Yeap I really don't know how to treat 12 V battery.
It's in series with the Thevenin voltage. (But oppositely oriented.)
 
Doc Al said:
It's in series with the Thevenin voltage. (But oppositely oriented.)

Can you give some more hint please...
 
Do this: Find the Thevenin voltage just before the 12 V battery. Then you can add the 12 V battery in series with it.
 

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