Solve Troublesome Integral Homework Problem

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Homework Statement



Here is the problem: http://img810.imageshack.us/i/skjghl.jpg/
(I failed repeatedly to write the problem with forum latex code)

Homework Equations



N/A

The Attempt at a Solution


I thought that since the integrand is nonzero only when b - E - p = 0, the integral would be equal to all the constant terms times the area of a sphere with radius given by b - E - p = 0 (that is, p = (b^2 - a^2)/2b), but I wound up with the wrong answer.
 
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\omega = 2 \pi G^2 \int \frac{ d^3p}{(2\pi)^3} \frac{f^2 a^2}{2E}\delta(b - E - p)

E = \sqrt{a^2 + p^2) and a,b,f and G are constants.

Show that \omega = \frac{ G^2 f^2 a^2 b (1 - \frac{a^2}{b^2} )^2}{8\pi}

We are integrating with respect to which variables? Is p a function of a single variable?
 
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We are integrating over all space for the single variable p.

You've made a small typo, the Dirac's delta function isn't supposed to be squared, but thanks for the heads up on the bug and for putting my question into forum latex code =].
 
I edited it to fix the typo.
And I fixed another typo. I had p instead of b listed as a constant.
 
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I still don't understand the notation completely. This is 3D space, right? What is d ?
Is d^3 a constant or a notation for a derivative?
 
d^{3}p is like the dx usually found at the end of integrals, and it means that we integrate the variable p over all of the 3D space. It should be at the end, but for some reason many people (at least among physicists) like to put it right after the integration symbol.
 
How does the constraint p = \frac{ b^2 - a^2} {2b} define a surface of any kind?

The letter p [/tex] denotes some function p(x,y,z) , right? Is p(x,y,z) = \sqrt(x^2 + y^2 + z^2)?
 
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