1. Jan 18, 2012

### Kinetica

1. The problem statement, all variables and given/known data

Hey guys, recently, I struggled to solve this equation.
I need to find θ1 and θ2 by using this system of equations:

θ12
θ12

After letting θ2=β/θ1, I plugged this into the first equation. I got:

θ12-γθ1+β=0

At this point I get a very unsexy θ1 result by using quadratic solution.

Need you help!

P.S. This way, I get 4 solutions overall, but my professor is saying that there should only be 2 solutions.

2. Jan 18, 2012

### Dick

What you've done so far is just fine. And I don't think the answer is going to pretty no matter how you do it.

3. Jan 19, 2012

### Ray Vickson

How did you get 4 solutions? Could you show us? The point is that you must have made an error, and we cannot help until we know what you did.

RGV

4. Jan 19, 2012

### epenguin

If you look at your equations they are symmetric between θ1 and θ2. You could say there is no difference between θ1 and θ2. Or, do what you did to get a quadratic equation for θ1 but do it to get an equation for θ2 instead - you find you have got exactly the same equation for θ2 as you got for θ1.

You haven't really got two quadratic equations, you've got one.