I Solve Velocity Equation: -g(horizontal distance)/sin(2theta)

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The discussion centers on a velocity equation related to projectile motion, specifically velocity = sqrt((-g)(horizontal distance)/sin(2theta). The user expresses confusion about the equation's validity and its application, particularly regarding the angle and gravitational constant. An example is provided where a ball is thrown 290 feet at an angle of 26 degrees, resulting in a calculated velocity of approximately 108.52 ft/sec, which the user finds questionable. They also compare this to their own experience of throwing a ball at 8 degrees, leading to a calculated velocity of 42 ft/sec, which seems inconsistent given the ball's actual landing distance. The main inquiry seeks clarification on the equation's origin and correctness in the context of projectile motion.
LT72884
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So i was googling the mighty google for a general question on velocity and i happened upon this equation with no description of it. Only states it is a velocity equation

velocity=sqrt((-g)(horizontal distance)/sin(2theta))

sorry, symbols is not working on me laptop at the moment

Its been a LONG while since physics for me but i do not recal this equation.

an example was given of:
distance a ball was thrown = 290 feet
g= -32
angle ball was thrown was 26* ( i assume horizontal is 0* but sin 0 = o which can't have in denominator so something seems odd)

they end up with roughly 108.52 ft/sec

this eq seems strange to me. i threw a ball at roughly 8* and it took 1.002 seconds to go 15feet. if i plug that into me equation i get 42 feet/s

that doesn't sound right to me because after 1.002 seconds, the ball landed at 15 feet, so it can't be going 42 feet/sec then.

ANYWAY my MAIN QUESTION IS... WHAT EQUATION IS THIS HAHAHA

thanks
 
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