Solving 8-j3)5e^-jsomething Complex Phasor Problem

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To solve the complex phasor problem involving (8-j3)5e^-jsomething, the first step is to convert the first factor into polar form. This results in (8-j3)*5*exp(-jx), which simplifies to Sqrt(73)*exp(-j*0.3588)*5*exp(-jx). The final expression can be represented as 5*Sqrt(73)*exp(-j*(x+0.3588)), leading to the cosine form of 42.72*Cos(wt - x - 0.3588). It is essential to ensure that the phasors are of the same frequency, w, for accurate conversion.
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I can convert sinusoids to phasors and vice versa if they are relatively simple, but I don't know how to deal with these two.

(8-j3)5e^-jsomething.

I was going to distribute, and make two vectors and find the resultant vector, but I don't think that's how to go about it. also

Thanks ver much for any hints or secrets.
 
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I don't know how to deal with these two
Where's the second one?
Just put the first factor into polar form and multiply, like so:
(8-j3)*5*exp(-jx) = Sqrt(73)*exp(-j*0.3588)*5*exp(-jx) = 5*Sqrt(73)*exp(-j*(x+0.3588))
which converts to 42.72*Cos(wt - x - 0.3588), assuming, of course, that the phasors are of the same frequency, w.
 
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