Solving a 135 N Vertical Force Problem

  • Thread starter Thread starter lilbilly
  • Start date Start date
  • Tags Tags
    Force Vertical
AI Thread Summary
A 135 N vertical force is applied to a bracket held by screws at points B and C, requiring the replacement of this force with an equivalent force couple system at B. The moment of force P about point B was calculated to be 54 N*m, derived from the force and distance. The horizontal forces at B and C were determined to be 750 N and 500 N, respectively, with a question raised about the possibility of both having the same force of 500 N. The discussion highlights the importance of showing work in problem-solving and the challenges faced when applying special triangles in related problems. Ultimately, the original question was resolved, but further assistance was sought for another problem.
lilbilly
Messages
1
Reaction score
0

Homework Statement



http://img407.imageshack.us/img407/5642/resumestuff004bm5.jpg

A 135 N vertical force P is applied to A to the bracket shown, which is held by screws at B and C. (a) Replace P with an equivalent force couple system at B. (b) Find the two horizontal forces at B and C that are equivalent to the couple obtained in part a.

Homework Equations





The Attempt at a Solution



Well, I tried to find the moment of force P about the hinge and then match that moment with an opposite one by a force at point B...but I really don't know what I'm doing.
 
Last edited by a moderator:
Physics news on Phys.org
We'd like to help but your diagram is unviewable.
 
I think the sketch shows a 125 mm outstanding leg length, with the other leg attached with 2 screws 75 mm apart. So what did you get for the moment of Force P about point B? What must be the horizontal force magnitude and direction at point C to balance that moment? And what must be the magnitude and direction of the horizonntal force at point B?
 
hey guys same question, except the vertical force at p is 300N

the distance from A to the block is 180mm, B to horizontal piece of bracket is 72 mm, and 108 mm from b to c.

21297id.jpg


just read we should show our work, for a i got 54N*m, from 300*0.180m, but I am not sure if this is correct
for part b, i just divided the answers by the respective distances and got 750n and 500n
 
Last edited:
is it possible that both B and C could have the same force of 500N?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top