Solving a Football Kicking Problem with PreCalc

  • Thread starter Thread starter mandomansion
  • Start date Start date
  • Tags Tags
    Precalc
AI Thread Summary
Scott's football kicking problem involves calculating the trajectory of a kick with an initial velocity of 50 ft/sec at a 65-degree angle from a height of 3 feet. The correct equations for the horizontal and vertical motion are x(t) = (50 * cos 65)t and y(t) = -16t^2 + (50 * sin 65)t + 3, with 32 ft/s² as the acceleration due to gravity. The maximum height of the ball is approximately 107.694 feet, and it lands about 190.178 feet away from Scott. The total time the ball is in the air was not calculated due to time constraints. Proper settings on the TI-83 calculator are crucial for accurate results in such problems.
mandomansion
Messages
5
Reaction score
0
Scott kicked a football with an initial velocity of 50 ft/sec at an angle of 65 degrees with the horizontal and at a height of 3 feet. Write the equations that would model this situation and answer the following:

a)
x(t) = _____________ (fill in formula with variable values plugged in)
y(t) = _____________ (fill in formula with variable values plugged in)

b) What is the max height of the ball?
c) How far did the ball land from Scott?
d) How long was the ball in the air?


Calculator problem if that wasn't obvious enough.




Formulas:

x(t) = (V * cos x)t
y(t) = -0.5gt^2 + (V * sin x)t + h




My attempts: (which are wrong by the way)

a)
x(t) = (50 * cos 65)t [CORRECT]
y(t) = -0.5(9.8)t^2 + (50 * sin 65)t + 3 [ITALICIZED PART IS WRONG; I figured g stood for gravity, so 9.8, right?]

b)
107.694 ft (didn't get formula right, and probably didn't use calculator correctly, so these are probably far off)

c)
190.178 ft.

d)
Didn't have enough time to finish.





This is a pretty quick PreCalc problem if you know what you're doing (which I didn't), so it would really help if one could do this.

And if one could tell me what mode settings my TI-83 should be on when I do this, I'd appreciate it.

And I apologize; in my 1AM rush to figure this problem out so I don't get another 10 points off on another test, I posted this in the wrong forum.
 
Last edited:
Physics news on Phys.org
You were right in thinking that g stood for gravity, it simply is a matter of units. 9.8 represents the acceleration in m/s^2, whereas you're working with feet in this problem!
 
Bah, so what would the correct # be?
 
32 right?
 
Right.
 
Thank you very much. My test grades will finally get the justice they deserve.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top