Solving a Nitrogen Can Homework Statement

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Homework Help Overview

The discussion revolves around a physics problem involving a can filled with nitrogen gas, focusing on pressure, volume, temperature, and related calculations. The subject area includes gas laws and thermodynamics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss various calculations related to the gas properties, including volume at standard temperature and pressure (STP), mass of nitrogen, change of pressure with temperature, and energy per molecule. Some participants question the validity of assumptions made in the calculations and the appropriateness of certain values used.

Discussion Status

There is an ongoing exchange of corrections and clarifications regarding the calculations. Some participants have revised their answers based on feedback, while others continue to explore the implications of their assumptions and the correctness of their methods.

Contextual Notes

Participants note potential issues with unit conversions and the need for clarity on the definitions of certain terms, such as energy per molecule versus total energy. There is also mention of the importance of using consistent temperature values in calculations.

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Homework Statement


A can filled with nitrogen has pressure 10 Pa, volume 10 cm3, and temperature 300 K.
(i) Find the volume at STP
(ii) Find the mass of the nitrogen
(iii) Find the change of pressure over temperature at 300 K
(iv) Find the energy of each molecule of nitrogen

Homework Equations


PV = nRT

The Attempt at a Solution


(i)
[tex]\frac{P_1 V_1}{P_2 V_2}=\frac{n_1 R T_1}{n_2 R T_2}[/tex]

Assuming n1=n2 : ------> Is this right ?

[tex]\frac{10*10}{10^5*V_2}=\frac{300}{273}[/tex]

[tex]V_2=2.73 x 10^{-3}\; m^3[/tex](ii)
P1V 1= nRT1
10*10-5=n *8.31* 300
n = 4.011 x 10-8 mole

m = n*Mr = 4.011 x 10-8*28 = 1.12308 x 10-6(iii) Is the question asking the change at 300 K compared to STP ?

[tex]\frac{\Delta P}{\Delta T}=\frac{P_2-P_1}{V_2-V_1}=\frac{10-10^5}{10^{-5}-2.73 x 10^{-3}}\approx 3.68 x 10^7 \frac{Pa}{m^3}[/tex] ??(iv)
[tex]E=\frac{3}{2}nRT[/tex]

Not sure about using T = 300 K or T = 273 K (STP)

Thanks
 
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(i) Incorrect input value for volume - should be in m3. Also, the value "2.73" is suspicious. The ratio 300/273 is close to one and the other side is all powers of 10.

(ii) Mass calculation looks OK, but no units are given.

(iii) Method OK but calculation needs to be redone because it depends on answer in (i).

(iv) 300 K is not much different from 273 K. Expression is incorrect. You are asked to find the energy per molecule, not the total energy.
 
Hi kuruman

I've revised my answer for the (i), (ii), and (iii) according to your correction :)

For the last one :

[tex]\text{Energy per molecule}=\frac{3}{2}\frac{nRT}{N_A} ??[/tex]

where NA = Avogadro's constant

Thanks
 
For the total energy of an ideal gas, I prefer the form

[tex]E = \frac{3}{2}N k T[/tex]

where N is the number of molecules and k the Boltzmann constant. Then the energy per molecule is simply
[tex]\epsilon = \frac{3}{2}k T[/tex]
 
Hi kuruman

Ok I get it now.

Thanks a lot for your help :smile:
 

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