Solving a Thermodynamics Problem: Finding ΔHf for OH(g) in H2O2 (g) Reaction

  • Thread starter Thread starter Dell
  • Start date Start date
  • Tags Tags
    Thermodynamics
Click For Summary
SUMMARY

The discussion focuses on calculating the enthalpy of formation (ΔHf) for hydroxyl radicals (OH(g)) in the reaction of hydrogen peroxide (H2O2(g) → 2OH(g)). The given dissociation enthalpy (ΔH(diss)) is 213 kJ/mol, which is stated to equal twice the ΔHf of OH. Participants clarify that ΔH(diss) represents the enthalpy change for the reaction, and to find ΔHf(OH), one must utilize the enthalpy of formation values for H2O2 from standard tables and apply the enthalpy of reaction formula.

PREREQUISITES
  • Understanding of thermodynamic concepts, specifically enthalpy of formation.
  • Familiarity with chemical reaction equations and stoichiometry.
  • Ability to reference and interpret thermodynamic tables for enthalpy values.
  • Knowledge of the relationship between dissociation enthalpy and formation enthalpy.
NEXT STEPS
  • Research the enthalpy of formation values for H2O2 from reliable thermodynamic tables.
  • Learn how to apply the enthalpy of reaction formula: ΔH = ΣΔHf(products) - ΣΔHf(reactants).
  • Study the concept of dissociation enthalpy and its relation to formation enthalpy in chemical reactions.
  • Explore examples of similar thermodynamic calculations involving radical species.
USEFUL FOR

Chemistry students, educators, and professionals in the field of thermodynamics or chemical engineering seeking to deepen their understanding of enthalpy calculations and radical chemistry.

Dell
Messages
555
Reaction score
0
How do i solve this chem, thermodynamics problem?
find ΔHf for OH(g) if

H2O2 (g)--> 2OH(g)

ΔH(diss)=213KJ/mol

what is ΔH(diss)?? what is 'diss'

someone told me The ΔH(diss)=213KJ/mol is equal to twice the ΔHf of OH. but i doont know how they got to this, also it seems a bit too simple for a qestion if all i need to do is divide by 2,
so how would i solve this?
 
Physics news on Phys.org
Your [tex]\Delta H(diss)[/tex] is your enthalpy of reaction. Remember that the enthalpy of reaction equals: Enthalpy of formation of products - Enthalpy of formation of reactants. Replace your data (you will need to look for H2O2 enthalpy of formation on a table) there and solve for [tex]\Delta H(OH)[/tex].
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
14K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 8 ·
Replies
8
Views
9K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 1 ·
Replies
1
Views
24K