Solving a Virtual Image Problem Involving a Converging Lens

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SUMMARY

A converging lens with a focal length of 0.246 m creates a virtual image located 0.933 m from the lens on the same side as the object. The correct formula to use for this scenario is 1/f = -1/di + 1/do, where di is the image distance and do is the object distance. The calculated object distance is do = 0.197157 m, which is incorrect due to a misapplication of the lens formula. The correct approach requires careful attention to the signs of the distances involved.

PREREQUISITES
  • Understanding of lens formulas, specifically 1/f = 1/di + 1/do
  • Knowledge of virtual images and their properties in optics
  • Familiarity with the concept of focal length in converging lenses
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Review the derivation and application of the lens formula for converging lenses
  • Study the characteristics of virtual images formed by lenses
  • Practice problems involving different object and image distances with converging lenses
  • Explore the impact of varying focal lengths on image formation
USEFUL FOR

Students studying optics, physics educators, and anyone seeking to understand the principles of lens behavior and image formation.

lpau001
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Homework Statement



A converging lens of focal length 0.246 m forms a virtual image of an object. The image appears to be .933 m from the lens on the same side as the object. What is the distance between the object and the lens?


Homework Equations


1/f = 1/di + 1/do

Since the image is virtual, it would be a negative distance right?

so 1/f = -1/di + 1/do


The Attempt at a Solution


I get do = (.246)(.993)/(.246+.993) = .197157 m
which is wrong..
 
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The formula1/f=1/di - 1/do
 

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