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NAkid

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## Homework Statement

A 35.0kg beam is attached to a wall with a hinge and its far end is supported by a cable. The angle between the beam and the cable is 90o. If the beam is inclined at an angle of theta=14.0o with respect to horizontal, what is the horizontal component of the force exerted by the hinge on the beam? (Use the `to the right' as + for the horizontal direction.)

## Homework Equations

## The Attempt at a Solution

i know that the horizontal force at pivot must be equal and opposite to horizontal force of tension. so for torques i have

LTsin(theta) = (L/2)mgcos(theta)

Ls cancel

so Tsin(theta) = (1/2)mgcos(theta)

but I don't know what I'm solving for exactly.. when I draw the free body diagram I have that F(horiz)=Fcos(theta), which seems to contradict my equations... help please!