Solving Chain Rule Problem with Equation (7.8)

  • Thread starter Thread starter Robin04
  • Start date Start date
  • Tags Tags
    Chain Chain rule
Robin04
Messages
259
Reaction score
16

Homework Statement


https://digitalcommons.usu.edu/cgi/viewcontent.cgi?article=1007&context=foundation_wave
I'm trying to understand this paper and I'm stuck at equation (7.8). That part of the text is very short so I hope you don't mind if I don't copy the equations here.

Homework Equations

The Attempt at a Solution


I understand how I get (7.7). But if I want to take the second derivate I can just apply the chainrule again. ##\partial_t^2{q} = \partial_t{[v(\partial_u{\tilde{q}}-\partial_s{\tilde{q}})]} = v[\partial^2_u{\tilde{q}}\partial_t{u}-\partial^2_s{\tilde{q}}\partial_t{s}] = v^2[\partial^2_u{\tilde{q}}+\partial^2_s{\tilde{q}}]##
But in the text it looks like if the author raised it to the power two (and got a different result) and I don't see why is that the same operation as taking the second derivative.
 
Physics news on Phys.org
I posted too soon, I realized what I did wrong. ##\partial_u{\tilde{q}}## is also dependent on s and so does the derivative with respect to s depend on u. With this, I got the same result.
 
First of all, what is your background in math? Do you understand what is second partial derivative?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Replies
12
Views
2K
Replies
4
Views
1K
Replies
3
Views
1K
Replies
4
Views
2K
Replies
4
Views
2K
Replies
7
Views
1K
Replies
3
Views
2K
Back
Top