Solving Charge Accumulated from Scuffing Feet: Magnitude of Force

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A person accumulates a net charge of -72.1 µC from scuffing her feet, which translates to approximately 4.5E14 excess electrons. To find the force on a single electron at a distance of 6.03 m, Coulomb's law is applied, where the charge of the person is used as one value and the charge of an electron (1.6E-19 C) as the other. The correct formula is F = k * (Q1 * Q2) / r^2, where Q1 is the accumulated charge and Q2 is the charge of the electron. The confusion arises in determining the correct values for Q1 and Q2 in the equation. Ultimately, the force calculation should use the net charge of the person and the charge of a single electron to yield the correct result.
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Homework Statement


Part A (which I already got right) A person scuffing her feet on a wool rug on a dry day accumulates a net charge of -72.1 uC. How many excess electrons does this person get?
Part B (Which is what I need help on) Given the static charge buildup in the previous question, what is the magnitude of the force on an electron at a distance 6.03 m from the person?

Homework Equations


So i thought that what you would do is simply find how many coulombs are in an electron, which is 1.6E-19 C. Then convert the uC to C and you would get .000072 C or 7.2E-5 C. So i divided the 7.2E-5 by the 1.6E-19 and got 4.5E14 which was the correct answer. But the part I need help with is finding the magnitude of the force. I would think I could just use coulombs law but I am not really sure what my q1 and q2 would be. Would I use 7.2E-5 and the 4.5E14? or would i use something else?


The Attempt at a Solution


I did
F=((8.9E9)(4.5E14)(7.2E-5))/6.03^2 and got an answer of 7.9E18 N. which was wrong. not sure where i went wrong
 
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Yes colombs law, its asking you what force a SINGLE electron would experience, 6.03m away from the person..

Try treating the person as a single charge. Find out what the charge of an electron is, and try colombs law.
 
Well the charge of a single electron is 1.6E-19 C. so would it be then
F=(8.9E9)(1.6E-19)/6.03^2? cause i tried that and it was still wrong. Would the equation just be then kQ/r^2 or would it be kQ^2/r^2
just not sure
 
Colombs law is F = \frac{kQ_1Q_2}{r^2}

It measures the force two charges exerts on each other at a given distance r. So if one charge is the charge of an electron, the other charge is?
 
thank you so much. got it. so it was using the charge of the net charge from what i was given. the 7.2uC
 
I'm stuck on this problem too. Did you end up using
(k)(charge of girl)(charge of electron)/r^2?
 
you do k(charge of how many she accumulated)(charge of electron)/r^2
 
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