- #1
rbtqwt
- 4
- 0
Hi. I have a problem in trying to find the field \vec E in the following situation:
I have an infinite charged plane, with charge density \sigma, and two dielectrics, like in picture:
http://img53.imageshack.us/img53/2301/testrb0.jpg
Now, if i think of \vec D being orthogonal to the charged plane, using Gauss law i get \vec D = \frac{\sigma}{2} \vec k, then i get the fields \vec Ein the dielectrics: \vec E_1 = \frac{\sigma}{2\varepsilon_0 k_1} \vec k and \vec E_2 = \frac{\sigma}{2\varepsilon_0 k_2} \vec k.. but, because of \oint \vec E \cdot d\vec x = 0, I obtain E_{t_1} = E_{t_2} , where E_{t_i} is the tangential (to the contact surface of dielectrics) component of \vec E in dielectric i. But E_{t_1} = \|\vec E_1}\| \ne \|\vec E_2\| = E_{t_2}.
What is wrong?
I have an infinite charged plane, with charge density \sigma, and two dielectrics, like in picture:
http://img53.imageshack.us/img53/2301/testrb0.jpg
Now, if i think of \vec D being orthogonal to the charged plane, using Gauss law i get \vec D = \frac{\sigma}{2} \vec k, then i get the fields \vec Ein the dielectrics: \vec E_1 = \frac{\sigma}{2\varepsilon_0 k_1} \vec k and \vec E_2 = \frac{\sigma}{2\varepsilon_0 k_2} \vec k.. but, because of \oint \vec E \cdot d\vec x = 0, I obtain E_{t_1} = E_{t_2} , where E_{t_i} is the tangential (to the contact surface of dielectrics) component of \vec E in dielectric i. But E_{t_1} = \|\vec E_1}\| \ne \|\vec E_2\| = E_{t_2}.
What is wrong?
Last edited by a moderator:
