Solving Energy Conservation for Pendulum Movement

AI Thread Summary
The discussion focuses on using conservation of energy to determine the speed of a pendulum at various angles. The pendulum has a length of 0.50 m and a speed of 2.15 m/s at its lowest point. Participants suggest calculating the height at different angles and applying the conservation of mechanical energy equation, which equates potential and kinetic energy. It is emphasized that mass cancels out in the equations, allowing for speed calculations without needing its value. The final formula provided for speed at any angle is v = SQRT(2gl(1 - cos(θmax)).
jim the duke
Messages
23
Reaction score
0

Homework Statement



Conservation of energy: looking for equations to solve the following

Homework Equations



A pendulum with length l = 0.50 m and with a negligible mass. The string is attached to a fixed point A and the pendulum swings in a vertical plane.

The pendulum has a speed v = 2.15 m s–1 at the lowest point of its swing.

I need to work out the pendulums speed at intervals so 10,20,30,40 degrees

The Attempt at a Solution


I have already calculated the time period of the swing to T = 2 pi sqrt l/g, which means T= 1.59s, also the height of the swing from lowest point to end is 0.49m

Any help would be great, thanks
 
Physics news on Phys.org
Why not use conservation of energy.
 
How would i use it to get the speeds at intervals though?
 
jim the duke said:
How would i use it to get the speeds at intervals though?
Figure out the height of the pendulum at each of those points.
 
I've already worked out the swing heights at any given interval, its the speed in m/s i need.
Thanks
 
jim the duke said:
I've already worked out the swing heights at any given interval, its the speed in m/s i need.
How would you express conservation of mechanical energy for the pendulum?
 
Pass?
 
v=SQRT(2*KE/m).
 
jim the duke said:
v=SQRT(2*KE/m).
OK, that how to get velocity from KE.

What's an expression for the total energy of the pendulum?
 
  • #10
E = mgL[1 - cos(θ0)] ?
 
  • #11
jim the duke said:
E = mgL[1 - cos(θ0)] ?
That will give you the gravitational PE, measured from the lowest point.

What's the total energy?
 
  • #12
Sorry i don't know
 
  • #13
jim the duke said:
Sorry i don't know
Look up total mechanical energy (and conservation of energy) in your textbook.
 
  • #14
Tme = pe + ke
 
  • #15
jim the duke said:
Tme = pe + ke
Good!

That's conserved as the pendulum moves.
 
  • #16
Ok so now what - total mech en = pot en + kin en
What step do i take next?
 
  • #17
jim the duke said:
Ok so now what - total mech en = pot en + kin en
What step do i take next?
Energy is conserved. It remains constant:

E1 = E2

PE1 + KE1 = PE2 + KE2

Let position 1 be the lowest point; position 2 being any other position you need to solve for.
 
  • #18
How do i get the speed from that equation though?
 
  • #19
jim the duke said:
How do i get the speed from that equation though?
Once you have the KE at each point, then you can get the speed using KE = 1/2mv^2. (See the equation you showed in post #8.)
 
  • #20
But i still have no figure for Mass so i cannot calc - KE = 1/2mv^2
 
  • #21
jim the duke said:
But i still have no figure for Mass so i cannot calc - KE = 1/2mv^2
When you write your energy conservation equation, you'll see that mass (which appears in both the PE and KE terms) will drop out. You won't need it.
 
  • #22
Im lost, i give up
 
  • #23
jim the duke said:
Im lost, i give up
You know the expressions for PE and KE, just plug them into the conservation of energy equation in post #17.
 
  • #24
V= SQRT 2gl(1-cos∅max)
 

Similar threads

Replies
9
Views
2K
Replies
7
Views
4K
Replies
31
Views
3K
Replies
5
Views
2K
Replies
5
Views
1K
Replies
14
Views
2K
Back
Top