1. The problem statement, all variables and given/known data OK, I need to solve for the fixed point of the equation 2sinπx + x = 0 on the interval [1, 2]. I know the answer to be ~1.21... but I need to prove it. 3. The attempt at a solution I really just need help solving for a proper equation of x. I tried x = -2sinπx, but that doesn't work on the interval for the method I am using to solve for the fixed point (Banach). So I tried this 2sinπx = -x sinπx = (-x/2) πx = arcsin(-x/2) x = (1/π)*arcsin(-x/2) But this equation seems totally wrong, as anything past 0 is negative. Can anyone tell me what I'm doing wrong, or perhaps that there is another way to solve for x? Thanks.