Solving for Acceleration using V^2=V0^2+2a(x-x0)

V^2-V0^2)/(2(x-x0))In summary, the initial velocity of a hockey puck is 49 m/s and the final velocity is 35 m/s. It travels 25 m during this time and using the equation V^2=V0^2+2a(x-x0), the acceleration can be calculated as a = (V^2-V0^2)/(2(x-x0)), where V is the final velocity, V0 is the initial velocity, and (x-x0) is the distance traveled.
  • #1
tball665
1
0
1. A hockey puck has an initial velocity of 49 m/s and a final velocity of 35 m/s. If it travels 25 m during this time, what is the acceleration?


2. V^2=V0^2+2a(x-x0)



3. I can't even begin the above equation because I don't know what my velocity is. I tried putting my final velocity in the above equation as V^2 and got -.28 m/s^2. It was wrong. I am assuming that is not how the equation is supposed to be used. Please help!
 
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  • #2
welcome to pf!

hi tball665! welcome to pf! :smile:

(try using the X2 and X2 buttons just above the Reply box :wink:)

V is the final velocity, and Vo is the initial velocity :wink:
 
  • #3


since (X-X0) is 25-0

you can move variables around and solve for a
 

FAQ: Solving for Acceleration using V^2=V0^2+2a(x-x0)

1. How do I solve for acceleration using the equation V^2=V0^2+2a(x-x0)?

The first step is to identify the given variables. V represents the final velocity, V0 represents the initial velocity, a represents acceleration, x represents the final position, and x0 represents the initial position. Then, plug in the values into the equation and solve for a.

2. What is the significance of the V0^2 term in the equation V^2=V0^2+2a(x-x0)?

The V0^2 term represents the initial velocity squared. This term accounts for the initial velocity's effect on the final velocity and must be considered when solving for acceleration.

3. Can this equation be used to solve for acceleration in any situation?

No, this equation can only be used when the object is moving with a constant acceleration. If the acceleration is not constant, a different equation or method must be used to solve for acceleration.

4. How can I use this equation to find the final velocity of an object?

If all other variables are known, the final velocity (V) can be solved for by rearranging the equation to V = √(V0^2+2a(x-x0)). Then, plug in the values for V0, a, x, and x0 to solve for V.

5. Is there a graphical representation of this equation?

Yes, this equation can be represented graphically by plotting the position (x) on the x-axis and the velocity (V) on the y-axis. The slope of the line on the graph represents the acceleration (a).

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