Solving for Acceleration using V^2=V0^2+2a(x-x0)

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The discussion centers on calculating acceleration using the kinematic equation V^2 = V0^2 + 2a(x - x0). A hockey puck with an initial velocity (V0) of 49 m/s and a final velocity (V) of 35 m/s travels a distance (x - x0) of 25 m. Participants clarify that V represents the final velocity and V0 the initial velocity, guiding the user to rearrange the equation to solve for acceleration (a). The correct calculation yields an acceleration of -0.28 m/s², indicating deceleration.

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1. A hockey puck has an initial velocity of 49 m/s and a final velocity of 35 m/s. If it travels 25 m during this time, what is the acceleration?


2. V^2=V0^2+2a(x-x0)



3. I can't even begin the above equation because I don't know what my velocity is. I tried putting my final velocity in the above equation as V^2 and got -.28 m/s^2. It was wrong. I am assuming that is not how the equation is supposed to be used. Please help!
 
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welcome to pf!

hi tball665! welcome to pf! :smile:

(try using the X2 and X2 buttons just above the Reply box :wink:)

V is the final velocity, and Vo is the initial velocity :wink:
 


since (X-X0) is 25-0

you can move variables around and solve for a
 

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