Solving for Airtime: Calculating Time in the Air of a Football Thrown at 21 m/s

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AI Thread Summary
To determine the total airtime of a football thrown at 21 m/s, the vertical component of the velocity must be resolved using the angle of projection. Given that the ball reaches its peak in 2.7 seconds, the time to ascend is equal to the time to descend, resulting in a total airtime of 5.4 seconds. The final vertical velocity at the peak is zero, allowing for the calculation of the angle of projection using kinematic equations. The discussion highlights the importance of understanding projectile motion principles to solve the problem effectively. Accurate calculations depend on applying the correct equations related to vertical motion.
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Homework Statement



A quarterback threw a football at 21 m/s at a certain angle above the horizontal. If it took the ball 2.7 s to reach the top of its path, how long was it in the air?


Homework Equations


i am confused, although you guys may find this to be simple. wat equations do i use?


The Attempt at a Solution

 
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You have the initial spped it was thrown at. Let it be thrown at some unknown angle thetha. The resolve the speed into the vertical component. By putting final velocity equal to zero, you can find theta, because you are given the time it takes. Then you can calculate how long it is in the air for.
 

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