Solving for F to Hold a Box Still on a Ramp w/ Friction

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    Box Friction Ramp
AI Thread Summary
To solve for the force F required to hold a box still on a ramp with friction, a free body diagram is essential for analyzing the forces acting on the box. The derived equation is F = (m*g*sinθ2) / (cosθ1 + μs*sinθ1), assuming the box is in equilibrium with zero acceleration. It is suggested to balance the forces in both horizontal and vertical directions for clarity, as the box's state of rest implies equilibrium. The discussion highlights the importance of defining the angles θ1 and θ2, as well as considering the effects of pushing versus pulling forces on the normal force and friction. Overall, the approach emphasizes the need for a comprehensive understanding of the forces at play in this scenario.
k-rod AP 2010
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Homework Statement


Write a General Formula solving for F to hold a box still on a ramp with friction.

there is no numbers in this, only variables

Homework Equations



F=ma

F=force m=mass a=acceleration θ=angle μs=static friction g=gravity

The Attempt at a Solution



i drew a free body diagram to separate the forces into components and plugged in the forces acting on the box to keep it from sliding of the frictioned ramp into F=ma

ma=Fcosθ1 - [(μs*Fsinθ1) + (m*g*sinθ2)]

then, i made ma equal to 0 b/c the box isn't moving so a is 0

0=Fcosθ1 - (μs*Fsinθ1) + (m*g*sinθ2)

This is the final equation i came up w/ after solving for F
F=(m*g*sinθ2) / (cosθ1 + μs*sinθ1)

would this be correct?
 
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Instead of making a=0 later its better you balance all the forces in horizontal and vertical direction since box is in equilibrium

There will be two conditions :
1) F is pushing force 2) F is pulling force

if condition (1), the Normal force increases thus increasing friction and just opposite in condition (2). You haven't mentioned what is θ2
 


theta2 is the angle the ramp is sloping at. theta1 is the angle the box is sloping at.

And do you mean have 1equation for horizontal forces and 1 equation for vertical? I am not sure what you mean
 
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