The problem talks about a ball, at rest, going down an inclined plane with an acceleration of 0.5 m/s^2. The inclined plane is 9 meters long. Once the ball gets to the bottom it goes back up another inclined plane. which is 15 meters long, it goes to rest. The question wants to know the speed when the ball is at the bottom of the first inclined plane. So, basically, the question stated that we have an acceleration of 0.5 m/s^2 but didn't tell us the time. So, to fin the time, I divided the acceleration by 9 meters, the distance. The answer would be a decimal with a unit of 1/s^2. Then, I inverted the decimal and got 18 s^2. Finally, I sqaure rooted the answer to get 4.24 seconds. My assumption was that this was the (delta)t. Now, to find the speed at the bottom of the inclined plane, I used d/(delta)t, where d is the total distance and (delta)t is the change in time. Thus, I did 9m/4.24s and got 2.12 m/s for the speed. However, the books answer was 3.00 m/s.