Solving for Speed of Blocks in Uniform Pulley System

AI Thread Summary
To find the speed of blocks m1 and m2 in a uniform pulley system after moving a distance d, the equation v = √(4gd/5) is derived. This calculation involves equating the change in gravitational potential energy of the blocks to their kinetic energy and the rotational kinetic energy of the pulley. The assumption is made that the tension in the massless strings remains constant, leading to equal speeds for both blocks. Additionally, the relationship between the linear speed of the blocks and the angular velocity of the pulley is established as v = rw. The solution highlights the importance of understanding energy conservation in the system.
Littlemstrouble
Messages
1
Reaction score
0

Homework Statement


A pulley is a uniform cylindrical disk of mass m and radius r. The strings are massless and there is no friction. If the system is initially at rest, find the speed of the blocks (m1 and m2) after they have moved a distance d.

m1----------0
**********l
**********l
**********l
**********m2

Homework Equations





The Attempt at a Solution


The answere should be v = square root(4gd/5)

 
Physics news on Phys.org
You'll need to look at the change in the gravitational potential energy of m1 and m2 and equate that to the kinetic energy of m1 and m2 plus the rotational kinetic energy of the disk. I don't believe your answer unless there is a special relation between m1, m2 and m.
 
If there is no friction, then tension in the string is constant and the speed of m1=m2. Now, v(m1)=v(m2)=rw where r is the radius of the disk and w is the angular velocity.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
5
Views
861
Replies
3
Views
2K
Replies
13
Views
7K
Replies
4
Views
3K
Replies
4
Views
4K
Replies
1
Views
2K
Replies
5
Views
5K
Back
Top