Solving for Velocity in a Three-Piece Explosion

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In the discussion about a firecracker explosion in a coconut, participants analyze the velocities of the resulting pieces. Two pieces of equal mass fly off at 20 m/s in perpendicular directions, while the third piece has double the mass. The momentum equations for both the X and Y directions are established, leading to the conclusion that the mass ratios will simplify the calculations. It is clarified that the specific mass values are not necessary for solving the problem, as they will cancel out. Ultimately, the velocities of the third piece can be derived from the momentum conservation principles.
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A firecracker in a coconut blows the coconut into three pieces. Two pieces of equal mass fly off south and west, perpendicular to each other, at 20 m/s. The third piece has twice the mass as the other two.What is the speed of the third piece?

really boggled, no masses are given? i thought since the mass is double then the speed would be half of the speed of the 1st and 2nd pieces? anyone have an equation to help me out?
thanks
 
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Resolve the momentums in the X and Y directions assuming the body is initially at rest:

\sum m_i v_i = 0 Here's the X direction (assuming east/west are the postive/negative x axis):

-20m + 2mv_x = 0

and in the Y direction:

-20m + 2mv_y = 0

It's easy to see what v_x and v_y are.
 
still don't understand, what do i put for the masses?
 
It doesn't matter what the masses are. The ratios are given. The masses will cancel out later once you have the relationship worked out.
 
so Vx = 10 and Vy = 10? after i solved in the equations
 
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