Solving Force of Friction for Homework

AI Thread Summary
To solve for the force of friction on a sled being pulled at a constant velocity with a horizontal force of 80 N at a 53-degree angle, it's essential to understand that the sled is not accelerating. A free body diagram is recommended to visualize the forces acting on the sled. The discussion highlights confusion around converting Newtons to grams, which is unnecessary for this problem. The key takeaway is that all forces should be measured in Newtons, and understanding the constant velocity condition is crucial for calculating friction. Proper guidance and clarification helped the participants grasp the problem better.
Makaroon
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Homework Statement



A sled pulled out a constant velocity across a horizontal. If a is a horizontal force of 8.0 x 10^1 N is applied at an angle of 53 degrees in the ground. What is the force of friction between the sled and the snow?

Homework Equations



I convert the N into grams?
and I have to put it into uh well you know one of those sine..


The Attempt at a Solution



well first I'm so confussed with the problem... eek, can someone please guide me through it?
 
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Why were you thinking in converting "N into grams"?
Do you have any ideia how would you calculate the friction force?

The key word in the problem is |constant velocity|.
Draw a free body diagram, it will help, I promiss.
 
One more small tiblite of information, all forces are measured in N.
 
oooh, yeah I got it now. thanks.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
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Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
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