Solving Frictional Force on Ladder

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SUMMARY

The discussion focuses on calculating the frictional force exerted on the bottom of a 12.0m ladder weighing 125 N, leaning against a smooth vertical wall at a 67-degree angle. A 14kg paint bucket is positioned 7.00m from the bottom of the ladder. The equations of motion discussed include the sum of forces in both x and y directions and the sum of torques. The solution involves first determining the normal force and then applying torque principles to find the friction force.

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Power of One
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Homework Statement


A ladder 12.0m long weighing 125 N rest against a smooth vertical wall. The bottom of the ladder makes an angel of 67 with the deck. A bucket of paint with a mass of 14kg rests o a rung, 7.00m from the bottom end of the ladder. What is the frictional force exerted on the bottom of the ladder?


Homework Equations


T= F x R x Cos theta

The Attempt at a Solution



Sum of forces x: Nw- fs=0
Sum of forces y= Ng- Fg=0
Sum of torques: Tnw- Tfg=0

Do I have these equations correct? I don't know which angles and lengths get plugged into which? Can someone please help me?
 
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Hi Power of One! :wink:

First find the normal force.

Then take moments to find the friction force. :smile:
 

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