Solving Initial Value Problem with f(x)=1 and erf(x)

ws0619
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Homework Statement


Consider the initial value problem y'+e^(x)y=f(x), y(0)=1.Express the solution of the initial-value problem for x>0 as a non elementary integral when f(x)=1 and also in term of erf(x)

Can somebody please help me solve this question?

Thanks!
 
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\frac{dy}{dx}+P(x)y=Q(x)

In this form use an integrating factor

e^{\int P(x)dx}
 
rock.freak667 said:
\frac{dy}{dx}+P(x)y=Q(x)

In this form use an integrating factor

e^{\int P(x)dx}

I am using integrating factor try to solve this question,but how can I form error function?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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