Muzikh
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Here's my problem. \int e^{1/x} dx
This was my attempt:
\int e^{1/x} dx , u = e^{1/x} , du = -\frac{ e^{1/x}}{x^{2}}
so, x^{2} du = - e^{1/x}
I = - \int x^{2} du , t = x , dt = (1) dx
I = \int x^{2} [\frac{ e^{1/x}}{x^{2}}] (1) dx = \int e^{1/x} dx
As you can see... I've only gone full circle with this approach. Any help would be greatly appreciated. Thanks.
This was my attempt:
\int e^{1/x} dx , u = e^{1/x} , du = -\frac{ e^{1/x}}{x^{2}}
so, x^{2} du = - e^{1/x}
I = - \int x^{2} du , t = x , dt = (1) dx
I = \int x^{2} [\frac{ e^{1/x}}{x^{2}}] (1) dx = \int e^{1/x} dx
As you can see... I've only gone full circle with this approach. Any help would be greatly appreciated. Thanks.