Solving Maximum Acceleration for 4WD Car on Dry Road

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The discussion focuses on calculating the maximum forward acceleration of a 1000kg four-wheel drive car on a dry road with a static friction coefficient of 0.8. The initial calculation provided uses the formula F = μ x Fn, resulting in a force of 7840N, which is then divided by the mass to yield an acceleration of 7.84 m/s². However, there is uncertainty about whether this calculation fully addresses the question posed. Participants agree that the calculation appears correct and sufficient for determining maximum acceleration without wheel spin. The thread concludes with reassurance that the approach taken is indeed valid.
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A car with four-wheel drive has a mass of 1000kg. Its weight is evenly distributed on its four wheels. The coefficient of static friction with the dry road is 0.8. The car starts from rest on a horizontal surface. What is the greatest forward acceleration that the car can ahcieve without spinning its wheels?

I simply said F = mu x Fn
= 0.8x1000x9.8=7840N

and divided that by the mass to get 7840 / 1000 = 7.84 m/s^2

But I feel that this is isn't correctly answering the question. Can anyone please help me out!?

Thanks
 
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I don't see what else u could do. Seems perfect 2 me
 

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