Solving Moments of Force: Finding A & B

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To find the forces at points A and B, the correct approach involves balancing the moments around point A. The equation used should include all forces acting on the system, including the neglected 2kN force at the left end. The distance between points A and B is also crucial for accurate calculations. The initial attempt mistakenly omitted these factors, leading to an incorrect result. Properly accounting for all forces and distances will yield the correct values for A and B.
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How do I find the force of A and B. I am taking moments at A but I am not getting the correct answer. (More Details below of attempt)

Homework Equations



Ʃ Of Clockwise Moments = Ʃ Of Anti-Clockwise Moments
Ʃ Of Upward Force = Ʃ Of Downward Force

The Attempt at a Solution



(THIS IS WRONG BUT THIS IS MY ATTEMPT)

A => (3x2)+(5x5)+(12x2)= Bx11
=> 6 + 25 + 24 = B x 11
=> 55 = B x 11
=> 55/11 = B
=> 5 = bTHANKS FOR HELP, I was trying this weekend and I need some genius advice so when I get this question again, I will be able to do so :)
 
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isigne said:
A => (3x2)+(5x5)+(12x2)= Bx11
I assume you're using A as your pivot point.
(1) You neglected the moment due to the 2kN force at the left end.
(2) What's the distance between B and A?
 
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