Solving O.D.E. Given Sequence (c, s, 1, e_1, e_{-1})

[VinnyCee]

Problem:

The sequence (c, s, 1, e_1,\,e_{-1}) is a basis for the solution space of some differential equation p(D)y = 0. Find this O.D.E.

NOTE: c = cos(t) and s = sin(t)


Work so far:

I know that e_1 gives a (t - 1) and that the e_{-1} gives a (t + 1), but how do I solve for the 1! I think that the c and s give (t^2 - 1).

Also, can someone explain in detail or give a reference to what a Ker() is?

thanks

 

[0rthodontist]

Ker(x) means the kernel of the transformation x--the set of all values that x maps to the identity. In linear algebra that would be the set of all values that x maps to the zero vector. What exactly are e_1,\,e_{-1}?

 

[HallsofIvy]

Problem:

The sequence (c, s, 1, e_1,\,e_{-1}) is a basis for the solution space of some differential equation p(D)y = 0. Find this O.D.E.

NOTE: c = cos(t) and s = sin(t)


Work so far:

I know that e_1 gives a (t - 1) and that the e_{-1} gives a (t + 1), but how do I solve for the 1! I think that the c and s give (t^2 - 1).

I have no idea what you mean by this! Is it possible that e_1 and e_{-1} were supposed to be e^1 and e^{-1}[/itex]? If that is the case then the roots of the characteristic equation are i, -i, 0, 1, and -1. From that information, you should be able to find the characteristic equation and from that the differential equation.<br /> <br /> The problem as given (&quot;Find this O.D.E.&quot;) has no single solution. There exist an infinite number of differential equations having those functions as solutions. Why I am giving is the simplest linear, homogenous, differential equation.

 

[Office_Shredder]

I think he meant e^t and e^{-t} since c, s, and 1 are functions (well, e and 1/e would be functions too, but for these purposes would be equivalent to 1)