Solving Object's Velocity at Bottom of Frictionless Incline

AI Thread Summary
To solve for the object's velocity at the bottom of a frictionless incline with a decreasing angle, one must consider the angle as a function of time, θ(t) = θo - wt, where w is the rate of decrease. The initial attempt using the equation Vf^2 = Vo^2 + 2a∆x is flawed because it assumes constant acceleration, which is not applicable here. Instead, the problem requires setting up and integrating the equations of motion to account for the changing angle. The correct velocity formula involves √Lg(1 - cos(θ)) divided by √(sin(θo - θo cos(θo))). Understanding the integration of motion equations is crucial for arriving at the correct solution.
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Homework Statement


An object rests at the top of a frictionless incline with length L and angle θo. At the moment the object is released the angle begins to decrease at a constant rate w. Thus the angle as a function of time is θ(t)= θo-wt. Value of w is defined to be the rate such that at the instant the object reaches the bottom of the incline, θ(t)=0. Find the objects velocity when it reachs the bottom of the incline in terms of L, θo, and the gravitational constant.


Homework Equations



〖Vf〗^2=[Vo]^2+2a∆x

The Attempt at a Solution


I tried solving this by using the equation 〖Vf〗^2=[Vo]^2+2a∆x, with Vo=0 and ∆x=L.
I solved for a by adding up the forces moving in the x direction giving me: a= gsinθ. I plugged this in and got the answer Vf=(2(gsin(θ))(L))^(1/2) but I was wrong. The answer is (√Lg(1-cos(θ)))/(√(sin⁡〖θ_o-θ_o cos⁡〖θ_0 〗 〗 )
I don't understand where to even begin with this problem, please help me!
 
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You have to set up and integrate the equations of motion. The equation you are using only applies to constant acceleration.
 
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