Solving Pendulum Questions: Length, Quick Swings, Clocks, Mount Everest & Moon

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To create a pendulum with a long swing period, increase its length, as the period is directly proportional to the square root of the length. Conversely, a shorter pendulum will swing quickly, resulting in a shorter period. For a pendulum clock with a 2-second period, the required length can be calculated using the formula T = 2π√(l/g), where g is the acceleration due to gravity. A 1-second pendulum clock would require a specific length that can also be derived from this formula. Pendulum clocks would not keep accurate time on Mount Everest or the Moon due to variations in gravitational acceleration at those altitudes.
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Homework Statement


1) If you wanted to build a pendulum that took a long time to make a full swing, what would you have to do about the length?

2) what if you wanted the reverse- a quick-swinging pendulum?

3) If you want to make a pendulum clock with a period of 2 seconds, what should its length be?

what would be the length of you wanted a 1 second pendulum clock?

would these clocks still keep accurate time if you moved then to the top of Mount Everest or the Moon? Explain

Homework Equations


there is none...?


The Attempt at a Solution


i think it is based on common sense which i am lacking of...
 
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There is one formula which may be helpful, take a look at the mathematical pendulum formula (I'm assuming it's not a physical pendulum that we are dealing with, maybe?).

T = 2\pi \sqrt{\frac{l}{g}}

Give it a try with the maths now.
 
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