Solving Physics Questions: Acceleration & Friction Coefficient

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SUMMARY

The discussion focuses on solving two physics problems involving acceleration and the coefficient of friction. For the first question regarding a cart rolling down a ramp inclined at 27 degrees, the acceleration is calculated using the formula F=ma, resulting in an acceleration of 4.45 m/s². The second question involves determining the coefficient of friction between a coin and a book, where the coin begins to slide at an angle of 25 degrees. The relationship between the forces is established using f=μN, leading to the conclusion that the coefficient of friction can be derived from the equation μ = tan(25°).

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Knowledge of trigonometric functions in physics
  • Familiarity with the concept of normal force
  • Basic understanding of friction and its coefficient
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  • Study the derivation of acceleration on inclined planes using F=ma
  • Learn about the relationship between angles and forces in friction problems
  • Explore the concept of normal force in different scenarios
  • Investigate the implications of friction coefficients in real-world applications
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of acceleration and friction in practical scenarios.

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Hey guys! I REALLY need some help with my physics. Here is one of my two questions:

1) With what rate of acceleration will a cart roll down a ramp inclined at an angle of 27 degrees? Assume the wheels of the cart are frictionless

I have NO idea how to even get started.

Here is the second one, 2) A coin is placed on a book that is slowly opened. It is noted that the coin does not start to move until the opening angle is 25 degrees. What is the coeficient of friction between the book and the coin?

THANKYOU in advance if you can help at all!
 
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1.use F=ma for the first one. So mgxsinx27=ma, then gxsin27=a

2. Use f=un, so mgcos25=Normal.

Maybe use F-f=ma to find f then use f=un to find coefficient of friction
 
For question 1 I got 4.45 m/s ^2. But i don't understand why you used mgsin27. How do we know that's the force? and not mgcos27

For question 2 i don't understand how you went from force of friction = unormalforce to mgcos25 . I also don't see how it helps because we don't have the mass.
 
mgcos always equals the normal force. Unless its an object on the ground, which in that case w=n.

Alright. f=un. mgcosx25=n

f=uxmgcos25

mgxsin25=uxmgcos25

gxsin25=uxgcos25
g=9.8
solve for u
 

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