Solving Range & Height of Spring Gun Ball - 45° Angle

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The discussion centers on solving a physics problem involving a spring gun that launches a ball at a 45-degree angle, achieving a horizontal range of 32 feet. The main challenges include determining the maximum height of the ball and finding two angles for a reduced range of 20 feet. Participants express confusion over the lack of necessary information, particularly the time frame for the projectile's motion. Suggestions include visualizing the problem with a diagram and clearly listing known and unknown variables to facilitate problem-solving. Overall, the conversation emphasizes the importance of organizing information to tackle complex physics questions effectively.
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I am not sure I can solve this, I am confused that I do not have the information I need. I am lost and my prof is of little help.

A spring gun projects a ball at an angle of 45 degrees above the horizontal. The ball has a horizontal range of 32 feet. What is the maximum height to which the ball rises, and for the same initial velocity, what are the two angles for which the range is 20 feet.

Dont I need at least a time frame to solve this?

The best part is, the other two problems are even more vague to me.
 
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Draw a picture of what is going on in the problem, then write down what you know and show in words what you've done. That way if you made a mistake someone can help you. It may also be helpful to write down what you know and write down what you don't know, then you know what to solve for
 
Xo = 0
Yo = 0
Ax = 0
Ay = -9.8m/s
Angle Theta = 45
x = 32 feet ( 9.6 m, 960 centimeters)
 
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