Solving Schrodinger Equation for Y(x)=A Sin (x)=0

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ghostbuster25
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ive been asked to show that the function of Y(x) = A sin (x) = 0 is a solution to the equation of

d2Y(x)
dx2

+k2Y(x)=0

where the Y is meant to be the lowercase wavefunctio psi...i just can't get it to work on this :(

basiaclly I am completely stuck. I am not really sure what to do! any help would be much appreciated :)

many thanks
 
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yer that's what I've just been reading but i am unsure of the value of Y

thanks for quick reply :)
 
sorry what i meant was that i am unsure of the value of A in th function. I understand kind of how to do the rest its just the A that has thrown me

and also i made a mistake the function is Y(x) = A sin (kx) not as stated above
 
The A is a constant. It will be pretty obvious what that A is when you plug the solution into the differential equation. Do this and please show your work. I can't say much more until you have done that without giving away the answer.
 
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is a just the quantum numbers (n=1,2,3...)
ha ha i bet its right in front of me isn't it
 
Try doing it the other way round: try taking the solution, and differentiating it twice. See what that gives you.