Solving Schrodinger Equation for Y(x)=A Sin (x)=0

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Homework Help Overview

The discussion revolves around demonstrating that the function Y(x) = A sin(kx) is a solution to the Schrödinger equation d²Y(x)/dx² + k²Y(x) = 0. Participants express uncertainty regarding the value of the constant A and the process of substituting the function into the differential equation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to substitute Y(x) into the differential equation and compute derivatives. There is confusion about the constant A and its significance in the context of the equation. Some participants question the correct form of the function and express uncertainty about the differentiation process.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the role of the constant A and the steps needed to verify the solution. Some guidance has been offered regarding the differentiation process, but there is no explicit consensus on how to proceed.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the amount of direct assistance they can receive. There is also a correction regarding the function's form, which has implications for the discussion.

ghostbuster25
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ive been asked to show that the function of Y(x) = A sin (x) = 0 is a solution to the equation of

d2Y(x)
dx2

+k2Y(x)=0

where the Y is meant to be the lowercase wavefunctio psi...i just can't get it to work on this :(

basiaclly I am completely stuck. I am not really sure what to do! any help would be much appreciated :)

many thanks
 
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You're supposed to plug Y(x) into the differential equation and compute the derivatives.
 
yer that's what I've just been reading but i am unsure of the value of Y

thanks for quick reply :)
 
sorry what i meant was that i am unsure of the value of A in th function. I understand kind of how to do the rest its just the A that has thrown me

and also i made a mistake the function is Y(x) = A sin (kx) not as stated above
 
The A is a constant. It will be pretty obvious what that A is when you plug the solution into the differential equation. Do this and please show your work. I can't say much more until you have done that without giving away the answer.
 
Last edited:
is a just the quantum numbers (n=1,2,3...)
ha ha i bet its right in front of me isn't it
 
Why aren't you plugging the solution into the differential equation as I have asked you to do three times now?
 
Try doing it the other way round: try taking the solution, and differentiating it twice. See what that gives you.
 

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