Solving Simple Capacitors Homework: Q, V, E

  • Thread starter Thread starter HZXAHNLfzjSr
  • Start date Start date
  • Tags Tags
    Capacitors
AI Thread Summary
A voltmeter with a resistance of 150kΩ is connected to a 50μF capacitor, initially reading 20V. The charge on the capacitor at time t=0 can be calculated using Q=cv. The correct formula for the voltmeter reading over time is V=V0e^(-t/RC), which is essential for solving parts (b) and (c) of the homework. To find the time for 95% of the energy to dissipate, the energy equations E=1/2 CV^2 and E0=1/2 CV0^2 are used to relate the energies. The discussion concludes with the user confirming their understanding and solution approach.
HZXAHNLfzjSr
Messages
10
Reaction score
0

Homework Statement



A voltmeter of resistance 150kilo Ohms is connected across a 50 micro F capacitor. If at time t= 0 the voltmeter reading is 20V. Find

a) charge on capacitor at time t=o
b) voltmeter reading after 10s
c) the time which must elapse after t = o before 95% of the energy stored has been dissipated


Homework Equations



Q=cv
E=1/2 cv^2

The Attempt at a Solution



a) I used Q = cv
b) I used V = (Vo)(e) - (t/RC) formula but not getting the correct answer
c) I tried a bunch of things but didn't even get close to the answer.

So can someone show me how to solve (b) and (c).

Thanks!
 
Physics news on Phys.org
Also can someone tell me if it's

V = (Vo)(e) - (t/RC)

OR

V = (Vo)(e) ^ - (t/RC)

In the latter case, kindly explain how I'd solve this to get V.

Thanks!
 
HZXAHNLfzjSr said:
Also can someone tell me if it's

V = (Vo)(e) - (t/RC)

OR

V = (Vo)(e) ^ - (t/RC)

In the latter case, kindly explain how I'd solve this to get V.

Thanks!

It's the second equation

V=V_{0}e^{-\frac{t}{RC}}.

(It's easy to see that first one is wrong - it's dimensionally incorrect!)

If you know what is V_{0}, you know everything you need to solve the problem completely.
 
N-Gin said:
If you know what is V_{0}, you know everything you need to solve the problem completely.

You said that V0 is 20 volts and also be careful with the dimensions (kilo and micro etc).

part c) requires you to rearrange to get it in terms of t. Also you have to work out V (hint: voltage is 'energy per unit charge')
 
Well I am still unsure as to how to do part (c) :(

Can someone show me the steps?

Thanks!
 
For the c) part, just use the formula

E(t)=\frac{1}{2}CV^{2}(t).

It must be equal to 5% percent of the initial energy

E_{0}=\frac{1}{2}CV_{0}^{2}.
 
Thanks I figured it out and just confirmed it with your posts ;)
 
Back
Top