Solving Siphoning Problem: Pressure, Diameter & Height

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AI Thread Summary
To solve the siphoning problem, the key is to understand the relationship between pressure difference, tube diameter, and flow rate. The pressure difference can be calculated using the formula pressure = rho * g * h, where rho is the water density, g is gravitational acceleration, and h is the height difference of 64 cm. To determine the flow rate, additional equations related to fluid dynamics and the specific characteristics of the tube, such as diameter (1.2 cm), must be applied. It's important to review relevant fluid mechanics principles to derive the flow rate from the pressure difference and tube dimensions. Understanding these concepts will facilitate the calculation of the siphon’s flow rate effectively.
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Homework Statement



Consider a siphon which transfers water from one vessel to a second (lower) one. Determine the rate of flow if the tube has a diameter of 1.2 cm and the difference in water levels of the two containers is 64 cm.

Homework Equations



Not sure what equations to use.

The Attempt at a Solution


I missed class the other day and so far only understand pressure=rho*g*h really. I need some help as to what to do and what equations to use for this.
 
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From what you have here, you can calculate only the pressure difference from one end of the hose to the other. You need to go back into your book and see how to get water flow rate given pressure and tube diameter.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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