Solving Spacetime Homework: Time, Displacement & Clocks

AI Thread Summary
The discussion focuses on solving a spacetime homework problem involving a spaceship traveling at 2c/3. Key calculations include determining the ship's time, Earth's time, and displacements for both the ship and light. The participant expresses uncertainty about their answers, particularly regarding Earth's time, which appears negative and raises questions about the problem's clarity. There is also confusion about whether the 3 meters refers to the ship's rest length. Despite the challenges faced, the participant notes that the problem did not appear on their final exam, alleviating some pressure.
chevycamaro1987
Messages
8
Reaction score
0

Homework Statement


spaceship 3 meters wide, v= 2c/3. (a.) calculate ships time, (b) sq. root factor, (c) Earth's time, (d) ships displacement, (e) lights displacement, and (f) which clock "runs slow"


Homework Equations


a. Ts=(3m)/c
b. square root 1-v^2/c^2
c. Earth's time = answer a/b (it tells me to use the two formulas actually, i figured this is equivalent)
d. ships displacement =vt
e. lights displacement= ct
f. which clock runs slow


The Attempt at a Solution


all of the formula have been given to me, i just want to make sure my answers are right.
a. 3m/3.00X10^8 m/s= 1X10^-8 s
b. sq. root 1-2X10^8= -1.9999999X10^8
c. t= -5X10^-17-----should this be a magnitude?
d. 2c/3*-5X10^-17= -1X10^-8 meters
e. ct= (3.00X10^8 m/s)(-5X10^-17) =-1.5X10^-8
g. i think i remember from the lecture that the Earth clock runs slow because of the displacement, it seems like it takes longer.

like i said, i just want to see if my work is right. i have a feeling c is wrong, because time shouldn't be negative. I am pretty sure the formulas are right because my teacher gave them in the book.
 
Physics news on Phys.org
Your problem statement is a bit vaque to say the least. What times are you talking about? Is 3m is the rest length of the ship?
 
OlderDan said:
Your problem statement is a bit vaque to say the least. What times are you talking about? Is 3m is the rest length of the ship?

I honestly don't know. Everything I was given I put in the problem word for word. But it's ok anyways, I took my final today and this problem wasn't on there, but it is kind of annoying that I can't figure it out.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top