Solving the distribution function

In summary, the conversation is about solving a complex double integration involving multiple variables and constants. The advice given is to simplify the integrand, use substitution, break down the integration, and seek help from online tools or peers.
  • #1
astro_enthu
3
0
I want to solve following double integration. I am stuck from long time. Any intermediate solution will also be appreciated.

[itex]\int[/itex][itex]\int[/itex] dvb dvl (feven+fodd)

where,

feven = (r*(vl[itex]^{2}[/itex]+vb[itex]^{2}[/itex]))^(-2*[itex]\beta[/itex])*(potential - 0.5*(vl[itex]^{2}[/itex]+vb[itex]^{2}[/itex]+vr[itex]^{2}[/itex]))^(-3*[itex]\beta[/itex]+5.5), where [itex]\beta[/itex],potential and vr are some constant numbers

fodd = (1-[itex]\eta[/itex])*tanh(r*vl*cos(b)/1000)*feven

Where, [itex]\eta[/itex], r,b are constant numbers. Which means I want to marginalise (feven+fodd) over vl and vb.

Integration limits for vl and vb comes from energy equation. Limits are -[itex]\sqrt{2*potential - vb[itex]^{2}[/itex] - vr[itex]^{2}[/itex]}[/itex]<=vl<=[itex]\sqrt{2*potential - vb[itex]^{2}[/itex] - vr[itex]^{2}[/itex]}[/itex] and -[itex]\sqrt{2*potential - vr[itex]^{2}[/itex]}[/itex]<=vb<=[itex]\sqrt{2*potential - vr[itex]^{2}[/itex]}[/itex]

Also -3.5< =[itex]\beta[/itex] <1
and 0<= [itex]\eta[/itex] <=2
Any help will be highly appreciated
 
Physics news on Phys.org
  • #2
.

Hello there,

Thank you for sharing your problem with us. It seems like you are trying to solve a complex double integration involving multiple variables and constants. Without knowing the exact values of the constants, it is difficult to provide a specific solution. However, I can give you some general advice on how to approach this problem.

Firstly, it is important to simplify the integrand as much as possible before attempting to integrate. In this case, you can simplify the expression (feven+fodd) by combining the terms and using properties of exponents. This will make the integration easier and more manageable.

Secondly, you can try using substitution to simplify the integrand further. Choose a variable to substitute and try to express the integrand in terms of that variable. This will help you reduce the number of variables in the integration and make it easier to solve.

Thirdly, it might be helpful to break down the double integration into two separate integrations, one for vl and one for vb. This will make it easier to apply the integration limits and solve each integration separately.

Lastly, do not hesitate to use online tools or software to help you with the integration. There are many resources available that can solve complex integrations and provide step-by-step solutions. You can also consult with your peers or a mentor for guidance and support.

I hope this information helps you in solving your problem. Keep persevering and don't give up, as solving complex integrations can be challenging but also rewarding. Good luck!
 

Related to Solving the distribution function

1. What is a distribution function?

A distribution function is a mathematical function that describes the probability of a random variable taking on a specific value or falling within a certain range of values. It is used to model and analyze data in many fields, including statistics, physics, and economics.

2. How is a distribution function solved?

The process of solving a distribution function varies depending on the specific function and its purpose. In general, it involves using mathematical techniques such as integration, differentiation, and numerical methods to find the function's parameters or to evaluate its values for given inputs.

3. What is the importance of solving distribution functions?

Solving distribution functions allows us to understand and analyze the behavior of random variables and make predictions about future outcomes. It also helps in making decisions based on data and evaluating the reliability of statistical models.

4. What are some common types of distribution functions?

Some commonly used distribution functions include the normal distribution, binomial distribution, exponential distribution, and Poisson distribution. Each of these functions has its own unique characteristics and applications in different fields.

5. Can distribution functions be solved analytically or only numerically?

Distribution functions can be solved both analytically and numerically. Analytical solutions involve finding exact mathematical expressions for the function, while numerical solutions involve approximating the function's values using computer algorithms or simulations.

Similar threads

  • Calculus
Replies
4
Views
1K
Replies
12
Views
1K
Replies
6
Views
1K
Replies
1
Views
2K
Replies
1
Views
1K
Replies
4
Views
483
Replies
4
Views
515
Replies
3
Views
311
Replies
3
Views
1K
Back
Top