Solving the Mystery of X Nucleus Binding Energy

AI Thread Summary
The binding energy of the X nucleus is 38.4 MeV, which indicates the mass deficit between the assembled nucleus and its constituents. The energy required to disassemble the nucleus is also 38.4 MeV, making statement B true. Statement C suggests that a 45 MeV photon would impart 6.6 MeV of kinetic energy to nucleons, which raises questions about photon interactions with nuclei. Statement D is debated, as binding energy is relevant to the formation of hydrogen atoms, typically referred to as ionization energy. The discussion emphasizes the complexities of photon energy effects on nuclear binding and interactions.
Darkmisc
Messages
222
Reaction score
31

Homework Statement


I have a multichoice past exam that does not come with answers. Please help with the following:

The binding energy of the X nucleus is 38.4MeV. Which of the following statements is FALSE?

a) The binding energy of 38.4MeV represents the mass deficit between the assembled nucleus and its constituents.
b) The energy required to disassemble the nucleus to its constituent parts is 38.4MeV
c) A photon of energy 45MeV will cause the component nucleons to move apart with kinetic energy of 6.6MeV.
d) The concept of binding energy cannot be applied to the assembly of a proton and an electron to form a hydrogen atom.


Homework Equations



none.

The Attempt at a Solution



I chose C. I have not come across fission caused by a photon. That said, I'm not sure what is supposed to happen when high energy photons strike nuclei.

I think D is true, but binding energy in that case is referred to as ionisation energy.
 
Physics news on Phys.org
If b is true, than c has to be true, wouldn't you think? You've supplied enough energy to break apart the nucleus, so why wouldn't it break apart?

By the way, a photon with energy of 45 MeV has a wavelength of 0.00002755 nm (compare to 400 nm - 700 nm for visible light) That's a hard gamma ray (i.e. a very energetic photon).

You may not have come across this, but it does have applications. For instance, in the early universe, big bang nucleosynthesis (the formation of light elements, mainly helium, from protons and neutrons through nuclear reactions) could not occur until the universe had expanded and cooled enough that very few photons were left in the radiation field that were more energetic than the binding energy of deuterium. That's because you have to make deuterium first, and build helium-4 out of it. That's called the deuterium bottleneck.

You might want to re-examine answer choice d.
 
Thanks.
 
[STRIKE]I have a different opinion. Think about this: what affect does a photon have on the constituent neutrons?[/STRIKE]

EDIT: Never mind, I was thinking about things backwards.
 
Last edited:
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top