Solving the Parallel Circuit: R=25, X[c]=100, X[L]=25

AI Thread Summary
The discussion focuses on calculating the combined impedance of a parallel circuit with given values: R=25, X[c]=100, and X[L]=25. The initial attempt at a solution yields an impedance of 20, but the expected answer is stated as 120. Participants clarify that the correct approach involves converting inductive and capacitive reactances to phasor form, leading to the conclusion that the correct impedance is actually j20. Additionally, it is emphasized that the equivalent impedance in a parallel circuit must be less than the smallest individual impedance, reinforcing that the answer cannot exceed 25. The conversation concludes with the consensus that the initial answer of 120 is likely a typographical error.
huma
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Homework Statement


what is the value combined impedance of the parallel circuit ?when R=25 ,X[c]=100 and X[L]=25

Homework Equations


I think we use this equation to solve parallel impedance ...
acp176.gif
.

The Attempt at a Solution


z=1/√((squ(1/25))+(squ((1/25)-(1/100))))=1/√(1/625)+squ(3/100)=√10000/25=100/5=20
but the ans is given is 120 what I do ?
 
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Hi,
with your value(R=25,XL=25,XC=100) and your equation you found the right answer. Maybe you forget to convert L and C value to phasor form, it means ( XL=JwL not XL= L) or the book answer is wrong
 
no its is given the value of Xc and XL ... no need to find Xc and XL
vetre
 
huma said:
but the ans is given is 120
Perhaps it is a typo. The answer is j20, not 120.
The equivalent impedance of a bunch of parallel impedances is less than the least of them, which means the answer is less than 25.
 

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