Solving the Ramp Problem: Finding Time to Stop Sliding on a Horizontal Surface

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An object slides down an incline at an angle of 6.9 degrees with a constant velocity of 1.4 m/s, transitioning onto a horizontal surface where the coefficient of friction is equal to that of the incline, calculated as 0.12101. The net force on the object is zero while on the incline, leading to the conclusion that the force of friction equals the parallel force. Once on the horizontal surface, the only force acting in the direction of motion is the friction force, resulting in a negative acceleration of -μg. By applying kinematic equations, specifically v = vo + at, the time taken for the object to come to rest can be determined using the known initial velocity and the calculated acceleration. This approach effectively solves the problem of finding the time it takes for the object to stop sliding on the horizontal surface.
Ninja_P
I would really appreciate some help on this problem, or even a push in the right direction:

An object of unknown mass slides down an incline in which Θ= 6.9. The object slides with a constant velocity of 1.4 m/s. At the bottom of the incline, the object slides on to a horizontal in which the coefficient of friction is the same as the incline. This is neglecting air resistance and the transfer of the object from incline to flat surface. I'm trying to figure out how long it will take the object to cease movement after it begins to slide on the horizontal surface.

So far I've been able to figure out:
Fnet = 0 since acceleration = 0.
Force of friction = Force parallel since Fnet = 0.
μ = 0.12101 because of tanθ = μ

Any help is greatly appreciated.
 
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Sorry, I forgot to add what equations I know already.

Of course, Fnet = ma
Normal Force = Weight x cosΘ On the horizontal -> W = mg
Parallel Force = Weight x sinΘ
Friction Force = μ x Weight x cosΘ (Normal Force)
and my four kinematics equations.
 
When you're on the horizontal part, the only force that is in the direction of motion is the friction force, which is now |f| = μmg. Let's define the direction of motion as the positive direction, so:

Fnet = -μmg
ma = -μmg
a = -μg

Now you have an acceleration that you can plug into your kinematic equations (vo is given as +1.4 m/s) to find the time to rest (v = vo+at is all you need for that).
 
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