Solving Trigonometric Ratios: Finding cosx/cosy from sinx/siny

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i got sinx/siny=1.2

and i need to find cosx/cosy

can i do it or maybe i need more knowledge?
 
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More information would help.
Context perhaps?
 
its a problem at optics and i need to solve this problem.
that all i know from the problem given.
 
It looks like you are trying to get an answer using an inefficient method.
What is the problem you are doing?
 
For example, if sin(x) and sin(y) are both positive, cos(x) and cos(y) could be positive or negative. So for one value of sin(x)/sin(y) there are two different possible values for cos(x)/cos(y).
 
Why would it matter, u can say that sinx worth 0.5 and that's mean that cosx is positive and negative too.i just need a trigonometric connection between the two
 
The general trig relationship between them is sin2θ + cos2θ = 1 because sinx and cosx are the opposite and adjacent sides of a right-angle triangle with unit hypotenuse.

if sinx=1/√2, then cosx=1/√2
But your problem is that you don't know what sinx is, what you know is the ratio of the sines of two angles ... sinx/siny.

In general: if sinx/siny=S, for a known S, then sinx and siny can take on any values that satisfy sinx=S.siny ... infinite possibilities. You need to know something about the relationship between x and y to narrow them down.

That is why I have asked for more information about the actual problem you are trying to solve.
Without that information, nobody can help you.
I do not understand your reluctance to share.
 
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