Solving Turbine Force: Vo = +21 m/s, Vf = -21 m/s, 27.2 kg/s

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The discussion revolves around calculating the average force exerted on a turbine blade by a stream of water. The incoming water velocity is +21 m/s, and the outgoing velocity is -21 m/s, with a mass flow rate of 27.2 kg/s. A participant suggests using the formula 21 * 27.2 to find the force, but questions arise regarding the correct application of Newton's third law and the need to consider the change in velocity. The correct approach involves calculating the total change in momentum, leading to the conclusion that the force should be 2(21)(27.2) due to the difference between the final and initial velocities. The discussion highlights the importance of understanding momentum change in force calculations.
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A stream of water strikes a stationary turbine blade, as the drawing illustrates. The incident water stream has a velocity of vo=+21 m/s, while the exiting stream has a velocity of vf=-21 m/s. The mass of water per second that strikes the blade is 27.2 kg/s. Find the magnitude of the average force exerted on the water by the blade.

(There is a pic of a turbine forcing water to make a 90 degree angle).

Wouldn't it be correct to say that the force by the water on the blade is equal to the force on the blade by the water due to Newton's 3rd law?

so just take 21 * 27.2 = 571.2? Why is this wrong according to my book?
 
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wouldnt it be 2(21)(27.2) because final-initial = -21-21=-42...
 
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